Answer
The distibution is symmetric.
$Mean=104.136~s$
$Median=104~s$
The mean better describes the length of eruption of this sample.
Work Step by Step
$Mean=\frac{2\times90+92+94+95+2\times99+2\times100+4\times101+3\times102+5\times103+3\times104+3\times105+2\times106+107+3\times108+2\times109+5\times110+111+113+116+120}{44}=104.136~s$
$Median=\frac{104+104}{2}=104~s$
Since the distribution is symmetric, the mean better describes the length of eruption of this sample.
