Answer
See the picture.
Work Step by Step
The heigth of the first bar (2003): $7.44-6.50=0.94$
The heigth of the last bar (2010): $9.81-6.50=3.31$
$\frac{The~heigth~of~the~last~bar}{The~heigth~of~the~first~bar}=\frac{3.31}{0.94}\approx3.5\gt3$
