Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 2 - Review - Review Exercises - Page 120: 6b

Answer

See the picture.

Work Step by Step

$Cumulative~relative~frequency=\frac{cumulative~frequency}{sum~of~all~frequencies}$ Total (sum of all frequencies): $4+13+19+7+3+2+1+0+1=50$ houses. The cumulative relative frequency for "50,000–99,999" is $\frac{4}{50}=0.08$ The cumulative relative frequency for "100,000–149,999" is $\frac{17}{50}=0.34$ The cumulative relative frequency for "150,000–199,999" is $\frac{36}{50}=0.72$ The cumulative relative frequency for "200,000–249,999" is $\frac{43}{50}=0.86$ The cumulative relative frequency for "250,000–299,999" is $\frac{46}{50}=0.92$ The cumulative relative frequency for "300,000–349,999" is $\frac{48}{50}=0.96$ The cumulative relative frequency for "350,000–399,999" is $\frac{49}{50}=0.98$ The cumulative relative frequency for "400,000–449,999" is $\frac{49}{50}=0.98$ The cumulative relative frequency for "450,000–499,999" is $\frac{50}{50}=1$
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