Answer
$T\gt T_\frac{α}{2}$: null hypothesis is not rejected.
There is not enough evidence to conclude that the median reaction time to the blue stimulus is different from the median reaction time to the red stimulus.
Work Step by Step
$H_0:M_D=0$ versus $M_D\ne0$
Let the "Reaction Time to Blue" values to be the X and the "Reaction Time to Red" values to be the Y.
$D_i=X_i-Y_i~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Rank$
$D_1=X_1-Y_1=0.582-0.408=0.174~~~~~~~~~+4$
$D_2=X_2-Y_2=0.481-0.407=0.074~~~~~~~~~+1$
$D_3=X_3-Y_3=0.841-0.542=0.299~~~~~~~~~+6$
$D_4=X_4-Y_4=0.267-0.402=-0.135~~~~~~-3$
$D_5=X_5-Y_5=0.685-0.456=0.229~~~~~~~~~+5$
$D_6=X_6-Y_6=0.450-0.533=-0.083~~~~~~-2$
$n=6$
Two-tailed test.
$T_+=4+1+6+5=16$
$|T_-|=|-3-2|=5$
$|T_-|\lt T_+$. So:
Test statistic: $T=|T_-|=5$
Critical value: $T_\frac{α}{2}=0$
(According to table XII, for $n=6$ and $\frac{α}{2}=0.025$)
Since $T\gt T_\frac{α}{2}$, we do not reject the null hypothesis.
