Answer
$H=17.199$
Work Step by Step
$H=\frac{12}{N(N+1)}[\frac{R_1^2}{n_1}+\frac{R_2^2}{n_2}+\frac{R_3^2}{n_3}]-3(N+1)=\frac{12}{122(122+1)}[\frac{2355.5^2}{31}+\frac{2119.5^2}{47}+\frac{3028^2}{44}]-3(122+1)=17.199$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 15 - Review - Review Exercises - Page 787: 6b
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