Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 14 - Section 14.3 - Assess Your Understanding - Vocabulary and Skill Building - Page 720: 13c

Answer

After removing $x_1$: $ŷ =282.3+1.143x_2+0.394x_3-2.957x_4$ $F_0=62.29$ with a P-value $\lt0.001\ltα$. The model is significant. After removing $x_3$: $ŷ =281.6+1.158x_2-2.627x_4$ $F_0=76.89$ with a P-value $\lt0.001\ltα$. The model is significant.

Work Step by Step

Let's remove $x_1$, the explanatory variable with the highest P-value (see item (b)). In MINITAB, enter the $x_2$ values in C2, the $x_3$ values in C3, the $x_4$ values in C4 and the $y$ values in C5. Select Stats -> Regression -> Regression -> Fit Regression Model Enter C5 in "Responses" and C2 C3 C4 in "Continuous Predictors" The least-squares regression line will be shown in "Regression Equation", where C5 is $ŷ$ , C2 is $x_2$, C3 is $x_3$ and C4 is $x_4$ Click OK. $ŷ =282.3+1.143x_2+0.394x_3-2.957x_4$ $F_0=62.29$ with a P-value $\lt0.001\ltα$ Now, let's remove $x_3$ because its P-value is greater than $α$: In MINITAB, enter the $x_2$ values in C2, the $x_4$ values in C4 and the $y$ values in C5. Select Stats -> Regression -> Regression -> Fit Regression Model Enter C5 in "Responses" and C2 C4 in "Continuous Predictors" The least-squares regression line will be shown in "Regression Equation", where C5 is $ŷ$ , C2 is $x_2$ and C4 is $x_4$ Click OK. $ŷ =281.6+1.158x_2-2.627x_4$ $F_0=76.89$ with a P-value $\lt0.001\ltα$
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