Answer
$R^2=0.9990=99.90$%
99.90% of the variation of the calories is explained by the model found in part (e).
$R^2_{adj}=0.99825=99.825$%
It adjusts the value of $R^2$, given the size of the sample, n, and the number of explanatory variables, k.
Work Step by Step
See the results in MINITAB, part (e).
$R^2=0.9990=99.90$%
$R^2_{adj}=1-(\frac{n-1}{n-k-1})(1-R^2)=1-(\frac{8-1}{8-3-1})(1-0.9990)=0.99825$
