Answer
$s_{b_1}=0.03871$
Work Step by Step
$s_e=0.9715$ (item (b))
To find $s_x$:
In MINITAB, enter the Temperature values in C1.
Select Stat -> Basic Statistics -> Display Descriptive Statistics
In Variables enter C1 and click in Statistics.
Select "Standard deviation". Click OK.
Click Ok.
$s_x=6.7073$
$s_{b_1}=\frac{s_e}{\sqrt {∑(x_i-x ̅)^2}}=\frac{s_e}{\sqrt {n-1}s_x}$ (see note on page 684)
$s_{b_1}=\frac{0.9715}{\sqrt {15-1}\times6.7073}=0.03871$
