Answer
$R^2=0.9020=90.20$%
90.20% of the variation of the price is explained by the model found in part (e).
$R^2_{adj}=0.88975=88.975$%
It adjusts the value of $R^2$, given the size of the sample, n, and the number of explanatory variables, k.
Work Step by Step
See the results in MINITAB, part (e).
$R^2=0.9020=90.20$%
$R^2_{adj}=1-(\frac{n-1}{n-k-1})(1-R^2)=1-(\frac{28-1}{28-3-1})(1-0.9020)=0.88975$
