Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 12 - Section 12.2 - Assess Your Understanding - Explaining the Concepts - Page 613: 23

Answer

The null hypothesis of the chi-square test for independence states that row variable and column variable are independent. It implies that the proportions in each column (or in each row) are the same, which is exactly the null hypothesis of the chi-square test for homogeneity. So, in both cases we use the procedures of the Goodness-of-Fit Test from section 12.1.

Work Step by Step

Given above.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.