Answer
$X_0^2=37.198$ with a P-value $\ltα$. Reject the null hypothesis.
There is enough evidence to conclude that the proportion of individuals is different for each level of education.
Work Step by Step
$H_0:$ the proportion of individuals is equal for each level of education.
versus
$H_1:$ the proportion of individuals is different for each level of education.
In MINITAB, enter the given values:
1-C1 = 302, 1-C2 = 551, 1-C3 = 29, 1-C4 = 100, 1-C5 = 46
2-C1 = 83, 2-C2 = 200, 2-C3 = 24, 2-C4 = 71, 2-C5 = 31
Select Stat -> Tables -> Chi-Square Test for Association
Select "Summarized data in a two-way table"
In columns containing the table enter: C1 C2 C3 C4 C5
Click OK.
$X_0^2=37.198$ with a P-value $\lt0.001\ltα=0.05$
