Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 12 - Review - Test - Page 616: 1

Answer

$X^2_0\lt X_α^2$: null hypothesis is not rejected. There is not enough evidence to conclude that the dice are not fair.

Work Step by Step

$H_0:$ the dice are fair versus $H_1:$ the dice are not fair In MINITAB, enter the observed values in C1 and the proportions in C2. Select Stat -> Tables -> Chi-square Goodness-of-Fit Test (One Variable) Select Observed counts and enter C1. Select specific proportions and enter C2. Click OK. $X^2_0=4.93985$ $k=11$. So, $d.f.=11-1=10$ $X_α^2=X_{0.01}^2=23.209$ (According to Table VII, for d.f. = 10 and area to the right of critical value = 0.01) Since $X^2_0\lt X_α^2$, we do not reject the null hypothesis. Also, P-value $=0.895\gtα$
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