Answer
$X_0^2=133.052$ with a P-value $\ltα$. Reject the null hypothesis.
There is enough evidence to conclude that the proportion of survivals is not equal for each class of service.
Work Step by Step
$H_0:$ the proportion of survivals is equal for each class of service.
versus
$H_1:$ the proportion of survivals is not equal for each class of service.
In MINITAB, enter the given values:
1-C1 = 203, 1-C2 = 118, 1-C3 = 178
2-C1 = 122, 2-C2 = 167, 2-C3 = 528
Select Stat -> Tables -> Chi-Square Test for Association
Select "Summarized data in a two-way table"
In columns containing the table enter: C1 C2 C3
Click OK.
$X_0^2=133.052$ with a P-value $\lt0.001\ltα=0.05$