Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.53 - 5.72 - Understanding the Principles - Page 249: 5.55b

Answer

$95$%

Work Step by Step

$z=\frac{x-\mu}{\sigma}=\frac{\mu\pm2\sigma-\mu}{\sigma}=\pm2$ According to table IV, page 773: $p(0\lt z\lt2)=.4772$ $p(-2\lt z\lt2)=2p(0\lt z\lt2)=2(.4772)\approx0.95=95$%
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