Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.20 - 5.52 - Applying the Concepts - Basic - Page 242: 5.39c

Answer

$p(x\lt35)=.0096$

Work Step by Step

$z=\frac{x-\mu}{\sigma}=\frac{35-50}{6.4}=-2.34$ According to table IV, page 773: $p(0\lt z\lt 2.34)=.4904$ $p(x\lt35)=p(z\lt-2.34)=p(z\lt0)-p(-2.34\lt z\lt0)=p(z\lt0)-p(0\lt z\lt2.34)=.5-.4904=.0096$
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