Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Applying the Concepts - Basic - Page 206: 4.64c

Answer

$p(x=2)=.264$

Work Step by Step

$p(x=2)=\begin{pmatrix} 5 \\ 2 \end{pmatrix}(.25)^2(.75)^{5-2}=\frac{5!}{2!(5-2)!}(.25)^2(.75)^3=10(.25)^2(.75)^3=.264$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.