Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 3 - Probability - Exercises 3.98 - 3.111 - Learning the Mechanics - Page 153: 3.102a


Let the 10 elements be {a,b,c,d,e,f,g,h,i,j}, then combinations will be: {aa,ab,ac,ad,ae,af,ag,ah,ai,aj, ba,bb,bc,bd,be,bf,bg,bh,bi,bj, ca,cb,cc,cd,ce,cf,cg,ch,cicaj, da,db,dc,dd,de,df,dg,dh,di,dj, ea,eb, ec, ed, ef, eg, eh, ei, ej, fa, fb, fc, fd, fe, ff, fg, fh, fi, fj, ga, gb, gc, gd, ge, gf, gg, gh, gi, gj, ha. hb, hc, hd, he, hf, hg, hi, hj, ia, ib, ic, id, ie, if, ig, ih, ii, ij, ja, jb, jc, jd, je, jf jg jh, ji, jj} Mathematically 10C2 = 10! / 2! (10-2)! = 10! / 2! 8! = 45

Work Step by Step

As given in answer
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.