Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 3 - Probability - Exercises 3.1 - 3.34 - Learning the Mechanics - Page 119: 3.9a

Answer

P($E_{3}$) = 0.5

Work Step by Step

P($E_{1}$)+P($E_{2}$)+P($E_{3}$)+P($E_{4}$)+P($E_{5}$)=1 Substituting the given probabilities, P($E_{3}$) = 1 - 0.1 - 0.2 - 0.1 - 0.1 P($E_{3}$) = 0.5
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