Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 2 - Methods for Describing Sets of Data - Exercises 2.71 - 2.89 - Learning the Mechanics - Page 64: 2.76c

Answer

Sample variance = $s^{2}=0.1868$ Sample standard deviation = $s =0.432$

Work Step by Step

Recall the shortcut formula for calculating the variance ($s^{2}$)$:$ $$s^{2}=\frac{\sum_{i=1}^{n}x_{i}^{2}-\frac{\left(\sum_{i=1}^{n}x_{i}\right)^{2}}{n}}{n-1}$$ Plug in the given values: $$\begin{align*} s^{2}&= \displaystyle \frac{18-\frac{\left(17\right)^{2}}{20}}{20-1} & & \\ & =0.1868 \\\\ s&= \sqrt{0.1868} =0.432 \end{align*}$$
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