Answer
$\mu$= 3.02, σ = 0.29, N =5540 students, n = 48
$\mu$ = $\mu$ _${\bar{x}}$= 3.02
σ_${\bar{x}\ }$ = $\frac{σ}{\sqrt n}$ = $\frac{.29}{\sqrt 48 }$ = 0.042
The sampling distribution has a greater extent of normal distribution since it has a smaller standard deviation compared to the population distribution. In other words, the spread in sampling distribution is smaller.
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