Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 6 - Section 6.2 - Standardizing a Normal Distribution - Exercises - Page 247: 6.20

Answer

a. From the given normal distribution, μ= 20 and σ= 4 . For x =20 : z = $\frac{20-20}{4}$ = 0 For x =27 : z = $\frac{27-20}{4}$ = $\frac{7}{4}$ = 1.75 $P(20 \leq x \leq 27)$ = $P( 0 \leq z \leq 1.75 )$ = 0.9599-0.5= 0.4599 approximately b. For x =23 : z = $\frac{23-20}{4}$ = $\frac{3}{4}$ = 0.75 For x =26 : z = $\frac{26-20}{4}$ = $\frac{6}{4}$ = 1.5 $P(23 \leq x \leq 26)$ = $P( 0.75 \leq z \leq 1.5)$ =0.9332-0.7734 =0.1598 approximately c. For x =9.5 : z = $\frac{9.5-20}{4}$ = $\frac{-10.5}{4}$ = -2.625 For x =17 : z = $\frac{17-20}{4}$ = $\frac{-3}{4}$ = -0.75 $P(9.5 \leq x \leq 17)$ = $P( -2.265\leq z \leq -0.75 )$ = 0.2266-0.0043 = 0.2223 approximately

Work Step by Step

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