## Introductory Statistics 9th Edition

μ = 45000 σ = 2000 miles $P(x \geq 46000)$ : z = $\frac{46000-45000}{2000}$ =$P(z \geq 0.5)$ = 0.3085 The probability that all four tires for her car will last at least 46,000 miles = 0.30854