Answer
P(has a GPS navigation system) = 0.636
P(does not have a GPS navigation system) = 0.364
Work Step by Step
Let f denote the number of cars that have a GPS navigation system, and N denote the total number of cars.
P(has a GPS navigation system) =$\frac{f}{N} $
$=\frac{28}{44}$
=0.636
Let f denote the number of cars that don't have a GPS navigation system, and N denote the total number of cars.
P(does not have a GPS navigation system) = $\frac{f}{N} $
$=\frac{16}{44}$
=0.364
