Answer
a.P(female|out-of-state)=$\frac{70}{125}$=0.56
P(female) = $\frac{110}{200}$=0.55
P(female ∩ out-of state) = $\frac{70}{200}$ = 0.35
Female and out-of-state are not independent since P(female|out-of-state) $\ne$ P(female) .
Female and out-of-state are not mutually exclusive since P(female ∩ out-of state) = 0.35 $\ne$ 0
b.
i. P(male) = $\frac{90}{200}$ = 0.45
ii. P(out-of-state student|female) = $\frac{70}{110}$ = 0.6364
Work Step by Step
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