Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 4 - Section 4.5 - Union of Events and the Addition Rule - Exercises - Page 162: 4.79

Answer

P(overweight) = $\frac{35.2}{100}$=0.352 P(obese) = $\frac{27.7}{100}$=0.277 P(obese or overweight) = 0.352+0.277 = 0.629 This probability is not 1.0 because there may be other possibilities of type of body weight, such as normal or underweight

Work Step by Step

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