Answer
a. P(red) = 0.5 , P(green) = 0.5
P(red at sixth time) = 0.5
When 5 red balls are removed from the box,
P( red) = $\frac{5}{15}$ = 0.33
P(red at sixth time) = 0.33
c. He is wrong. The probability will remain the same. Coin tossing is mathematically equivalent to the procedure mentioned in part a.
Work Step by Step
a. Because no red balls are removed from the box, the probabilities remain unchanged.
