Introductory Statistics 9th Edition

Published by Wiley
ISBN 10: 1-11905-571-7
ISBN 13: 978-1-11905-571-6

Chapter 3 - Self-Review Test - Page 123: 21

Answer

a. i. 75% ii. 84% b. Interval =[59.4, 132.3]

Work Step by Step

i. 91.8±k(16.2) = [59.4,124.2] 91.8-16.2k=59.4 k = 2 k=2, $1-\frac{1}{2^2} = 3/4*100 = 75%$ ii. 91.8±k(16.2) = [51.3,132.3] 91.8-16.2k=51.3 k=2.5 k=2.5, $1-\frac{1}{2.5^2} = (1-0.16) \times100 = 84%$ b. Interval = [91.8-2(16.2), 91.8+2.5(16.2)] =[59.4, 132.3]
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