## Introductory Statistics 9th Edition

$a. i)34±k(8) = [14, 54], 34-8k = 14, 20/8 = k k = 2.5$ $1-\frac{1}{2.5^2} = (1-0.16)\times100=84%$ ii) $34±k(8) = [18, 50], 34+8k = 50, 16/8 = k, k = 2$ $1-\frac{1}{2^2} = (1-0.25)\times100=75%$ b. $1-\frac{1}{k^2} = 0.89, 1/k^2=0.11 k = 3.015\approx 3$ $Interval = [34-(8)3, 34+8(3)]$ $=[10, 58]$