Chapter 5 - z-Scores: Location of Scores and Standardized Distributions - Problems - Page 147: 25

a. N = 5, scores = 0, 6, 4,3, 12 μ =$\frac{ 0+6+4+3+12}{5}$ = 5 SS = $∑z^{2} $ = σ =$ \sqrt (((0-5)^{2}+(6-5)^{2}+(4-5)^{2}+(3-5)^{2}+(12-5)^{2} )/5)$ = 4 b. As shown in the table. c. When N = 5, μ = 100, σ = 20, as shown in the table.

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