Essentials of Statistics for the Behavioral Sciences 8th Edition

Published by Cengage Learning
ISBN 10: 1133956572
ISBN 13: 978-1-13395-657-0

Chapter 5 - z-Scores: Location of Scores and Standardized Distributions - Problems - Page 146: 7

Answer

When μ = 60, σ = 12 A. X = 69, z =$\frac{X-μ}{σ}$ = $\frac{69-60}{12} $ = $\frac{9}{12}$ = 0.75 X = 84, z =$\frac{X-μ}{σ}$ = $\frac{84-60}{12}$ = $\frac{24}{12}$ = 2.0 X = 63, z =$\frac{X-μ}{σ}$ = $\frac{63-60}{12}$ = $\frac{3}{12}$ = 0.25 X = 54, z =$\frac{X-μ}{σ}$ = $\frac{54-60}{12}$ = $\frac{-6}{12}$ = -0.5 X = 48, z =$\frac{X-μ}{σ}$ = $\frac{48-60}{12}$ = $\frac{-12}{12}$ = -1.0 X = 45, z =$\frac{X-μ}{σ}$ = $\frac{45-60}{12}$ = $\frac{-15}{12}$ = -1.25 B. z= 0.50, X = 60+ 12z = 60+ (0.50)(12) = 66 z= 1.50, X = 60+ 12z = 60+ (1.50)(12) = 78 z= -2.50, X = 60+ 12z= 60+ (-2.50)(12) = 30 z=-0.25, X = 60+ 12z= 60+ (-0.25)(12) = 57 z=-0.50, X = 60+ 12z = 60+ (-0.50)(12) = 54 z= 1.25, X = 60+ 12z= 60+(1.25)(12) = 75

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