Answer
The mean for this population is $\mu$ = 5. The smallest distance and the largest distance is 1 point. The standard distance should be 1 point.
C. Mean = $\mu$ = $(1+3+3+3+4+4)/6$ =3
Variance = mean squared deviation = $6/6$ = 1
Standard deviation = $\sqrt 1$= 1
Work Step by Step
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