Chapter 4 - Measures of Variability - Problems - Page 116: 10

B. The mean for this population is $\mu$ = 5. The smallest distance from the mean is 1 point and the largest distance is 3 points. The standard distance should be between 1 to 3 points. C. Mean = $\mu$ = $(8+6+5+2+6+3+5)/7$ =5 Variance = mean squared deviation = $24/6$ = 4 Standard deviation = $\sqrt s^2$=$\sqrt 4$ = 2

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