## Essentials of Statistics (5th Edition)

$H_0: \mu = 0$ $H_1: \mu>0$ Test statistic: .133 $P>.1$, so don't reject the hypothesis.
We want to see if the mean change is greater than 0, so we know $H_0: \mu = 0$ and $H_1: \mu>0$. We now use a Ti-84 calculator. To solve, go to "Stat," then "Tests," and then select "Stats." Next, plug in 0 for $\mu_0$, .4 in for $\bar{x}$, 21 for $Sx$, and 49 for n. Then, select "$>\mu_0$" and push calculate. Doing this, we find that the test statistic, t, is .133. From this, we can find that $P>.1$, so we cannot reject the hypothesis.