Answer
a) 0, .36
.5, .48
1, .16
b) .4
c) Yes
Work Step by Step
a) First, we create the following table:
0, .36
.5, .48
1, .16
b) We find that the mean is:
$mean = (.5)(.48)+(1)(.16)=.4$
c) As is the case in this problem and as always is the case, the mean of the sampling distribution is equal to the population proportion.
