Answer
.0444
Work Step by Step
In order to solve this problem, we find the z-scores associated with $.67Q_1$ and $1.5Q_3$. Doing this and consulting the table of z-scores, we find that the probability of an outlier is .0444.
Essentials of Statistics (5th Edition)
by Triola, Mario F.
Published by
Pearson
ISBN 10:
0-32192-459-2
ISBN 13:
978-0-32192-459-9
Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 265: 37
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