Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Page 262: 24

Answer

a) .01 percent b) .01 percent c) No d) 70.1 inches

Work Step by Step

a) We find the z-score: $\frac{51.6-69.5}{2.4}=-7.46$ This is less than $-3.5$, so only about .01 percent of men can fit. b) We find the z-score: $\frac{51.6-63.8}{2.4}=-4.692$ This is less than $-3.5$, so only about .01 percent of women can fit. c) It does not, for most of the passengers cannot enter the aircraft without bending. d) We know that the z-score is .25. Thus, it follows: $=(.25)(2.4)+69.5=70.1 \ inches$
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