Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Page 228: 17

Answer

a) Mean:74. Standard deviation:7.38. b)It is unusually high.

Work Step by Step

Here, n=370 and p=0.2. a) Mean=$n\cdot p=370 \cdot 0.2=74$. Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{340 \cdot 0.2 \cdot 0.8}=7.38.$ b) If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=74-2\cdot7.38=59.24$ $Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=74+2\cdot7.38=88.76$. 90 is more than the upper bound, therefore it is unusually high.
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