Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - 4-6 Counting - Page 184: 40

Answer

$\frac{1}{3628800}$

Work Step by Step

$probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}=\frac{1}{10!}=\frac{1}{3628800}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.