Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 4 - Probability - 4-3 Addition Rule - Page 155: 31

Answer

$0.9145$

Work Step by Step

We know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$ and by the inclusion-exclusion principle:$P(A \cup B)=P(A)+P(B)-P(A\cap B)$. A:responded B:his/her age is between 22 and 29 or 30 and 39. By checking the data: $P(A)=\frac{1049}{1205}$ $P(B)=\frac{275+278}{1205}$ $P(A\cap B)=\frac{255+245}{1205}$ Therefore the probability of the person responding or his/her age being between 18 and 21: $P(A \cup B)=\frac{1049}{1205}+\frac{275+278}{1205}-\frac{255+245}{1205}=\frac{1102}{1205}\approx0.9145$
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