Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - Review - Cumulative Review Exercises: 5

Answer

a)190.125 mm b)195.5 c)18.67 mm d)$348.57 \ mm^2$ e)56 mm

Work Step by Step

a) The mean can be counted by summing all the data and dividing it by the number of data: $\frac{173+179+...+199}{8}=190.125 \ mm.$ b)The median is the average of the 1 or 2 (here 2) middle data: (195+196)/2=195.5. c)Standard deviation=$\sqrt{\frac{\sum (x-\mu)^2}{n-1}}=\sqrt{\frac{(173-190.125)^2+...+(199-170.125)^2}{7}}=18.67 \ mm.$ d) variance=$(standard \ deviation)^2=(18.67 \ mm)^2=348.57 \ mm^2.$ e) The range is the difference of the highest and the lowest data: 214 mm-158 mm=56 mm.
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