Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 6 - Confidence Intervals - Section 6.1 Confidence Intervals for the Mean - Exercises - Page 306: 30

Answer

n $\approx$ 25

Work Step by Step

1) The z-score corresponding to a 95% Confidence level is 1.96 2) Substitute z = 1.96, $\sigma$ = 2.5 and E = 1 into the formula: n = $(\frac{z \times \sigma}{E})^{2}$ n = $(\frac{1.96 \times 2.5 }{1})^{2}$ n $\approx$ 24.01 n $\approx$ 25
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