Answer
Answer: We can use the normal distribution to approximate the binomial. Hence, the mean = 11.1 and the standard deviation $\approx$ 2.644
Work Step by Step
n = 30, p = 0.37 and q = 0.63
np = 0.37 x 30 = 11.1
nq = 0.63 x 30 = 18.9
Since np $\geq$ 5 and nq $\geq$ 5, we can use the normal distribution to approximate the binomial distribution.
Hence:
Mean = np = 11.1
Standard deviation = $\sqrt{npq}$ = $\sqrt {30 \times 0.37 \times 0.63}$ $\approx$ 2.644