#### Answer

Given p = 69% = 0.59 and n = 4
a. Mean = n x p
= 4 x 0.69 = 2.76
b. Variance = n x p (1-p)
= 4 x 0.69 (0.31) = 0.8556
c. S.D = \sqrt Variance
=\sqrt 0.8556 = 0.9
d. On average 2.76 out of 4 adults think that musicians should be allowed to sing potentially offensive songs. The standard deviation is 0.9.

#### Work Step by Step

As given in answer