Answer
Yes, see explanations.
Work Step by Step
We first calculate some parameters from the data set.
$n=13, \bar X=9.6, s=0.585$
a. State the hypotheses and identify the claim.
$H_o: \mu\geq 10$
$H_a: \mu\lt 10$ (claim, left tail test)
b. Find the critical value(s).
$\alpha=0.05, df=12, t_c=-1.782$ negative for left tail test.
c. Compute the test value.
$t=\frac{9.6-10}{0.585/\sqrt {13}}=-2.47$
d. Make the decision.
Since $t\lt t_c$, we have enough evidence to reject the null hypothesis and support the claim.
e. Summarize the results.
At $\alpha = 0.05$, it can be concluded that the average weight is less than 10 ounces
