Answer
0.0075
Yes.
Work Step by Step
Given $\mu=272,\sigma=43,n=15$, we have
$z=\frac{299-272}{43/\sqrt {15}}=2.432$
Use Table E $P(X=299)=P(z=2.432)=0.9925$
so $P(X\gt299)=1-P(X=299)=0.0075$
The normal distribution is appropriate
here even the sample size is only 15
because the population is normally distributed.
