Chapter 6 - The Normal Distribution - 6-2 Applications of the Normal Distribution - Exercises 6-2 - Page 338: 6

a. $0.4602$ b. $0.0031$ c. $0.6687$

We have $\mu=982,\sigma=180$ a. More than 1000 $z1=\frac{1000-982}{180}=0.1,P(z>z1)=1-P(z1)=1-0.5398=0.4602$ b. More than 1475 $z2=\frac{1475-982}{180}=2.739,P(z>z2)=1-P(z2)=1-0.9969=0.0031$ c. Between 800 and 1150 $z3=\frac{800-982}{180}=-1.0111$ $z4=\frac{1150-982}{180}=0.9333$ $P(z3