Chapter 6 - The Normal Distribution - 6-2 Applications of the Normal Distribution - Exercises 6-2 - Page 337: 3

a. $0.201$ b. $0.432$

We have $\mu=706242, \sigma=52145$ a. $z1=\frac{750000-706242}{52145}=0.8392$ $P(z>z1)=1-P(z1)=1-0.7993=0.2007$ b. $z2=\frac{600000-706242}{52145}=-2.037$ $z3=\frac{700000-706242}{52145}=-0.1197$ $P(z2