Chapter 6 - The Normal Distribution - 6-1 Normal Distribution - Exercises 6-1 - Page 323: 45

1-.8962=.1038 -1.26

To find the z score given the area, we have to find the area under the curve to the left of the z score. Since we are given the area above the z score, we can subtract the given area from 100% of the area. This gives us .1038. We must then refer to table e in the back of the book. Locating the value nearest .1038, we can find that our z score is roughly -1.26