Chapter 5 - Discrete Probability Distributions - Review Exercises - Section 5-2 - Page 305: 14

4.92 dollars

Refer to the answer of Exercise 13, the expect value to win is now $\frac{3}{13}\times10-\frac{1}{13}\times20+\frac{1}{13}\times(2+3+4+5+6+7+8+9+10)=64/13=4.92$ So an amount of 4.92 dollars should be charged for the game to be fair.