Answer
a. $0.35$
b.
$\mu=1.55$
$\sigma^2=1.81$
$\sigma=1.34$
Work Step by Step
a. What is the probability that an employee will get 2
or 3 applications during any given shift?
Add up the corresponding probabilities: $p=0.20+0.15=0.35$
b. Find the mean, variance, and standard deviation for
this probability distribution.
Based on the definition and formula,
mean=$\mu=\sum xP(x)=1.55$
variance=$\sigma^2=\sum (x-\mu)^2 P(x)=1.81$
standard deviation=$\sigma=\sqrt {\sigma^2}=1.34$
